My Math Forum Help: Laurent Series

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 June 27th, 2018, 09:13 AM #1 Newbie   Joined: May 2018 From: south africa Posts: 11 Thanks: 0 Help: Laurent Series I need urgent help with the following: Find the Laurent series of the function 1/(z^3-z^4) with center z0=0 for (i) 0<|z|<1 and (ii) |z|>1 Any assistance will be great. Last edited by skipjack; June 27th, 2018 at 09:27 PM.
 June 27th, 2018, 10:50 AM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,165 Thanks: 1139 $\dfrac{1}{z^3 - z^4} = \dfrac{1}{z^3(1-z)}$ Now use partial fractions and find $A,~B$ such that $\dfrac{1}{z^3(1-z)} = \dfrac{A}{z^3} + \dfrac{B}{1-z}$ And use standard results to finish the problem. Thanks from greg1313
 June 27th, 2018, 09:45 PM #3 Global Moderator   Joined: Dec 2006 Posts: 19,865 Thanks: 1833 Expand 1/(1 - $z$), then divide each term by $z^3$.

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