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 April 23rd, 2018, 10:20 PM #1 Newbie   Joined: Jul 2017 From: KOLKATA Posts: 29 Thanks: 2 Calculus - Chain Rule Let f1(x) = e^x, f2(x) = e^f1(x) and generally fn+1(x) = e^fn(x) for all n . For any fixed n, Find the the derivative of fn(x) Please help Last edited by arybhatta01; April 23rd, 2018 at 10:22 PM.
 April 23rd, 2018, 11:21 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,814 Thanks: 1046 Math Focus: Elementary mathematics and beyond Hi arybhatta01. Have you made any progress solving this on your own? If so, can you post your work? If not, any thoughts on where to begin? Thanks from topsquark
 April 24th, 2018, 10:14 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,183 Thanks: 870 You mention the chair rule. If $\displaystyle f_{n+1}(x)= e^{f_n(x)}$, then, using the chain rule, $\displaystyle f_{n+1}'= e^{f_n(x)}(f_n(x)')$. I would be inclined to find the derivatives of the first three or four function, make a "guess" at derivative of the nth function, then try to prove that "guess" using induction. Thanks from greg1313 and topsquark Last edited by skipjack; April 24th, 2018 at 07:06 PM.
 April 24th, 2018, 10:53 PM #4 Newbie   Joined: Jul 2017 From: KOLKATA Posts: 29 Thanks: 2 Yes . It worked . We need to use chain rule to get the derivative of the 1st 3 function f1 f2,f3 and the use induction to get fn . Thanks.

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