March 31st, 2018, 03:37 PM  #1 
Newbie Joined: Dec 2017 From: Netherlands Posts: 21 Thanks: 0  Volume with Triple Integral
I have attached here solution to a problem. Please I wish to find out if my approach is correct

April 3rd, 2018, 11:56 AM  #2 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 
Your final answer, $\displaystyle \frac{\pi R^2z^2}{4}$, involves the variable z. That can't be right!

April 3rd, 2018, 12:43 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,786 Thanks: 708 
You wrote $z^2=x^2+y^2$. Wrong! Should be $r^2=x^2+y^2$. Try again!


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integral, triple, volume 
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