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March 31st, 2018, 03:37 PM   #1
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Volume with Triple Integral

I have attached here solution to a problem. Please I wish to find out if my approach is correct
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April 3rd, 2018, 11:56 AM   #2
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Your final answer, $\displaystyle \frac{\pi R^2z^2}{4}$, involves the variable z. That can't be right!
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April 3rd, 2018, 12:43 PM   #3
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You wrote $z^2=x^2+y^2$. Wrong! Should be $r^2=x^2+y^2$. Try again!
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