February 17th, 2018, 09:38 PM  #1 
Newbie Joined: Feb 2018 From: India Posts: 5 Thanks: 0 Math Focus: calculas, linear algebra, geometry, complex analysis,polynomials  calculus
integration from 0 to 1 (ln(1+x)/1+x*2)dx
Last edited by greg1313; February 17th, 2018 at 10:40 PM. 
February 17th, 2018, 09:42 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,090 Thanks: 1086 
do you really mean $\displaystyle \int_0^1 \dfrac{\ln(1+x)}{1} + 2x~dx$ ? because that's what you've written do you perhaps mean $\displaystyle \int_0^1 \dfrac{\ln(1+x)}{1+x^2}~dx$ ? 
February 17th, 2018, 09:48 PM  #3 
Newbie Joined: Feb 2018 From: India Posts: 5 Thanks: 0 Math Focus: calculas, linear algebra, geometry, complex analysis,polynomials 
2nd one


Tags 
calculas, calculus 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Calculas 3  bght  Calculus  2  February 11th, 2014 05:51 AM 
Calculas 3 (Stocks Theorem)  bght  Calculus  1  February 10th, 2014 08:03 PM 