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February 17th, 2018, 09:38 PM   #1
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calculus

integration from 0 to 1 (ln(1+x)/1+x*2)dx

Last edited by greg1313; February 17th, 2018 at 10:40 PM.
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February 17th, 2018, 09:42 PM   #2
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do you really mean

$\displaystyle \int_0^1 \dfrac{\ln(1+x)}{1} + 2x~dx$ ?

because that's what you've written

do you perhaps mean


$\displaystyle \int_0^1 \dfrac{\ln(1+x)}{1+x^2}~dx$ ?
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February 17th, 2018, 09:48 PM   #3
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February 17th, 2018, 10:31 PM   #4
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here
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February 18th, 2018, 03:46 AM   #5
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Already answered here.
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