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February 17th, 2018, 08:45 PM  #1 
Newbie Joined: Feb 2018 From: Pakistan Posts: 4 Thanks: 0 
Hi! I'm new here. I wanted help on a simple "Quadric Surface" Question from calculus 3. Our teacher in college didn't explained it in the class. Convert it into the standard form and sketch it: $x^2+y^2+z^2=3z$ Thanks! Last edited by skipjack; February 17th, 2018 at 08:49 PM. 
February 17th, 2018, 09:37 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,553 Thanks: 1403 
$x^2 + y^2 + z^2 = 3z$ $x^2 + y^2 + z^2 3z=0$ $x^2 + y^2 + \left(z\dfrac 3 2\right)^2  \left(\dfrac 3 2\right)^2=0$ $x^2 + y^2 + \left(z\dfrac 3 2\right)^2 =\left(\dfrac 3 2\right)^2$ can you identify what surface this is, it's center, and it's dimensions? 
February 18th, 2018, 02:09 AM  #3 
Newbie Joined: Feb 2018 From: Pakistan Posts: 4 Thanks: 0  Thanks man , I got it !


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calculus, quadric, question, surface 
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