My Math Forum Calculus 3 -Quadric Surface Question

 Calculus Calculus Math Forum

 February 17th, 2018, 08:45 PM #1 Newbie   Joined: Feb 2018 From: Pakistan Posts: 4 Thanks: 0 Hi! I'm new here. I wanted help on a simple "Quadric Surface" Question from calculus 3. Our teacher in college didn't explained it in the class. Convert it into the standard form and sketch it: $x^2+y^2+z^2=3z$ Thanks! Last edited by skipjack; February 17th, 2018 at 08:49 PM.
 February 17th, 2018, 09:37 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 1,980 Thanks: 1027 $x^2 + y^2 + z^2 = 3z$ $x^2 + y^2 + z^2 -3z=0$ $x^2 + y^2 + \left(z-\dfrac 3 2\right)^2 - \left(\dfrac 3 2\right)^2=0$ $x^2 + y^2 + \left(z-\dfrac 3 2\right)^2 =\left(\dfrac 3 2\right)^2$ can you identify what surface this is, it's center, and it's dimensions? Thanks from greg1313, Country Boy and hunter6
February 18th, 2018, 02:09 AM   #3
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Quote:
 Originally Posted by romsek $x^2 + y^2 + z^2 = 3z$ $x^2 + y^2 + z^2 -3z=0$ $x^2 + y^2 + \left(z-\dfrac 3 2\right)^2 - \left(\dfrac 3 2\right)^2=0$ $x^2 + y^2 + \left(z-\dfrac 3 2\right)^2 =\left(\dfrac 3 2\right)^2$ can you identify what surface this is, it's center, and it's dimensions?
Thanks man , I got it !

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