January 25th, 2018, 07:22 AM  #1 
Newbie Joined: Jan 2018 From: MI Posts: 11 Thanks: 1  Calc Help
I can't seem to figure out the answer for both these questions. Thank you

January 25th, 2018, 07:52 AM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,512 Thanks: 2514 Math Focus: Mainly analysis and algebra 
Start by remembering the definition of a continuous function. How could you apply this to each of the questions? 
January 25th, 2018, 07:53 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894 
Do you know the basic definitions? A function, f, is "continuous at x= a" if and only if $\displaystyle \lim_{x\to a} f(x)= f(a)$. What is the limit, as x goes to 4, of 4x? What is the limit, as x goes to 4, of $2x^2$? In order that the limit of f exist at x= a, those must be the same. The other one is basically the same, perhaps a little harder. What is the limit, as x goes to 4, of $\frac{8x^3 32x^2}{x 4}$? It helps to notice that $8x^3 32x^2= 8x^2(x 4)$. 
January 25th, 2018, 09:20 AM  #4 
Newbie Joined: Jan 2018 From: MI Posts: 11 Thanks: 1 
Thanks, I figured it out and got the answers!

February 12th, 2018, 04:53 PM  #5  
Senior Member Joined: Feb 2016 From: Australia Posts: 1,739 Thanks: 609 Math Focus: Yet to find out.  Quote:
 

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