My Math Forum stationary points of a trig function

 Calculus Calculus Math Forum

 December 23rd, 2017, 04:28 AM #1 Newbie   Joined: May 2017 From: uk Posts: 9 Thanks: 0 stationary points of a trig function Hi, am I doing this right? Find the coordinates when the gradient of this function is equal to zero t = cos(θ) f '(t) = -sin(θ) $\ \ \ \ \ \ \ \$ = -sin(θ) = 0 $\ \ \ \$ θ = 0/-sin $\ \ \ \$ θ = 0 Plug 0 in to original equation t = cos(0) t = 1 Coordinates = 0,1 where gradient is zero. Last edited by skipjack; December 23rd, 2017 at 08:27 AM.
 December 23rd, 2017, 05:13 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,856 Thanks: 1078 Math Focus: Elementary mathematics and beyond $\sin\theta$ is periodic.
 December 23rd, 2017, 08:30 AM #3 Global Moderator   Joined: Dec 2006 Posts: 19,521 Thanks: 1747 Having obtained -sin(θ) = 0, one cannot divide by "-sin". Instead, solve sin(θ) = 0 by using knowledge of the sin function.

 Tags function, points, stationary, trig

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Tom2000 Calculus 26 October 18th, 2016 12:12 PM ajrt3 Calculus 0 September 29th, 2014 12:10 PM ARTjoMS Calculus 2 January 9th, 2013 11:59 AM sahil112 Calculus 5 November 21st, 2012 11:51 AM wulfgarpro Algebra 5 May 30th, 2010 02:14 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top