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- - **stationary points of a trig function**
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stationary points of a trig functionHi, am I doing this right? Find the coordinates when the gradient of this function is equal to zero t = cos(θ) f '(t) = -sin(θ) $\ \ \ \ \ \ \ \ $ = -sin(θ) = 0 $\ \ \ \ $ θ = 0/-sin $\ \ \ \ $ θ = 0 Plug 0 in to original equation t = cos(0) t = 1 Coordinates = 0,1 where gradient is zero. |

$\sin\theta$ is periodic. |

Having obtained -sin(θ) = 0, one cannot divide by "-sin". Instead, solve sin(θ) = 0 by using knowledge of the sin function. |

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