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 November 23rd, 2017, 12:08 AM #1 Member   Joined: Jan 2017 From: Huddersfield Posts: 36 Thanks: 0 Pendulum theory A pendulum is swinging at a rate of 1.00586 seconds, to correct to 1 second what would the change in length of the pendulum be? Can this be worked out from the information given or is more info needed such as the weight of the pendulum? Can anybody show me how to work this out please
 November 23rd, 2017, 12:53 AM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,830 Thanks: 648 Math Focus: Yet to find out. You can play around with it here: Pendulum
November 23rd, 2017, 02:12 AM   #3
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Quote:
 Originally Posted by Jimkeller1993 A pendulum is swinging at a rate of 1.00586 seconds, to correct to 1 second what would the change in length of the pendulum be? Can this be worked out from the information given or is more info needed such as the weight of the pendulum? Can anybody show me how to work this out please
There is a key formula that allows you to answer this problem, which relates the physical parameters of a pendulum to its period:

$\displaystyle T = 2 \pi \sqrt{\frac{L}{g}}$

where:
T = Period of pendulum (s)
L = length of pendulum (m)
g = gravitational acceleration constant (take this to be 9.81 m/s$\displaystyle ^{2}$)

Note: this formula is great if the maximum angle of the swing is small. If it is large, then this formula can only be used as an approximation.

So... using this formula, you should be able to get its current length. Then you can derive the new length required to get the particular period you want. The change in length required is then just the difference between the two length results.

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