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November 9th, 2017, 08:55 AM   #1
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double integration

Please could someone help with this question. When me and a friend integrate this with respect to x first and then with y first we both get different answers of 1.13333 and 1.8588 respectively and we can't see where we are going wrong
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November 9th, 2017, 09:18 AM   #2
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$\displaystyle \int_0^{1/4} \int_x^{\sqrt{x}}~64x ~dy~dx + \int_{1/4}^{1/2} \int_x^{1/2}~64x~dy~dx = \int_0^{1/2}\int_{y^2}^y~64x~dx~dy = \dfrac {17}{15}$
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