November 9th, 2017, 09:55 AM  #1 
Member Joined: Dec 2015 From: England Posts: 30 Thanks: 0  double integration
Please could someone help with this question. When me and a friend integrate this with respect to x first and then with y first we both get different answers of 1.13333 and 1.8588 respectively and we can't see where we are going wrong

November 9th, 2017, 10:18 AM  #2 
Senior Member Joined: Sep 2015 From: Southern California, USA Posts: 1,602 Thanks: 816 
$\displaystyle \int_0^{1/4} \int_x^{\sqrt{x}}~64x ~dy~dx + \int_{1/4}^{1/2} \int_x^{1/2}~64x~dy~dx = \int_0^{1/2}\int_{y^2}^y~64x~dx~dy = \dfrac {17}{15}$


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