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 October 28th, 2017, 08:33 AM #1 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 integration Please integrate the following. the limits are L and 0. X(X-B)dx
 October 28th, 2017, 09:47 AM #2 Senior Member   Joined: Aug 2012 Posts: 2,384 Thanks: 743 Assuming that by X you mean x, that's a straightforward polynomial.
 October 29th, 2017, 03:17 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 $x(x- B)= x^2- Bx$ Do you know the anti-derivative of $x^2$? Bx?
 October 29th, 2017, 04:03 AM #4 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 in my view the correct answer is ((L^2)/6)*(2L-3B) but the book i am referencing shows the answer to be ((L^2)/6)*(2L-3B) + B^3 I dont understand where the B^3 came from
 October 29th, 2017, 04:47 AM #5 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,838 Thanks: 653 Math Focus: Yet to find out. $\int_0^L (x^2 - Bx) dx = \left[\dfrac{x^3}{3} - \dfrac{Bx^2}{2}\right]_0^L = \dfrac{L^3}{3} - \dfrac{BL^2}{2} = ((L^2)/6)*(2L-3B)$ Please post the full question as it appears in the text.
October 29th, 2017, 07:52 AM   #6
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