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October 28th, 2017, 09:33 AM   #1
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integration

Please integrate the following. the limits are L and 0.
X(X-B)dx
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October 28th, 2017, 10:47 AM   #2
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Assuming that by X you mean x, that's a straightforward polynomial.
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October 29th, 2017, 04:17 AM   #3
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$x(x- B)= x^2- Bx$ Do you know the anti-derivative of $x^2$? Bx?
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October 29th, 2017, 05:03 AM   #4
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in my view the correct answer is
((L^2)/6)*(2L-3B)

but the book i am referencing shows the answer to be

((L^2)/6)*(2L-3B) + B^3

I dont understand where the B^3 came from
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October 29th, 2017, 05:47 AM   #5
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Math Focus: Yet to find out.
$\int_0^L (x^2 - Bx) dx = \left[\dfrac{x^3}{3} - \dfrac{Bx^2}{2}\right]_0^L = \dfrac{L^3}{3} - \dfrac{BL^2}{2} = ((L^2)/6)*(2L-3B)$

Please post the full question as it appears in the text.
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October 29th, 2017, 08:52 AM   #6
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Please see attached full question
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File Type: jpg integration.jpg (15.4 KB, 6 views)
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