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October 27th, 2017, 07:35 AM  #1 
Senior Member Joined: Jan 2017 From: Toronto Posts: 209 Thanks: 3  Triple Integral of a complex geometric shape
Boundaries: z = 0 z = x + 2y z = 4  x  3y z = y Answer: $\displaystyle \int_{0}^{4} \int_{z}^{42z} \int_{z2y}^{4z3y} ~dx~dy~dz = \frac {32}{3} $ I would be much appreciated if anyone show me the steps of setting the above boundaries... 

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complex, geometric, integral, shape, triple 
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