My Math Forum Triple Integral of a complex geometric shape

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 October 27th, 2017, 07:35 AM #1 Senior Member   Joined: Jan 2017 From: Toronto Posts: 209 Thanks: 3 Triple Integral of a complex geometric shape Boundaries: z = 0 z = x + 2y z = 4 - x - 3y z = -y Answer: $\displaystyle \int_{0}^{4} \int_{-z}^{4-2z} \int_{z-2y}^{4-z-3y} ~dx~dy~dz = \frac {32}{3}$ I would be much appreciated if anyone show me the steps of setting the above boundaries...

 Tags complex, geometric, integral, shape, triple

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