My Math Forum Triple integral density of a strange shape.

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 October 16th, 2017, 08:13 AM #1 Senior Member   Joined: Jan 2017 From: Toronto Posts: 209 Thanks: 3 Triple integral density of a strange shape. x = 0 y = 0 z = 0 x + y = 1 z = x + 2y Density(x, y, z) = 3 + 2x + 2y - 2z Answer: 1/6 My Solution (not correct) $\displaystyle \int_{0}^{1} \int_{0}^{1-x} \int_{0}^{x+2y} (3+2x+2y-2z) ~dz~dy~dx = 5/3$ What did I do wrong?
 October 16th, 2017, 08:24 AM #2 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,166 Thanks: 738 Math Focus: Physics, mathematical modelling, numerical and computational solutions I get 5/3 also just calculating the integral you wrote down. Maybe the question/integral was written down wrong? Thanks from romsek and zollen

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