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February 24th, 2013, 06:20 AM   #1
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Challenging integral

Hello,

Here it is:

?sqrt(1+(2/3*x^-1/3)^2)
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February 24th, 2013, 06:33 AM   #2
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Re: Challanging integral

The challenging thing here is trying to read the integral , can you write it in latex ..
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February 24th, 2013, 06:57 AM   #3
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Re: Challanging integral



First let's make sure we're interpreting the integral correctly.
Does your integral look like the one above?
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February 24th, 2013, 08:35 AM   #4
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Re: Challanging integral

Yes, that's how it looks.
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February 24th, 2013, 08:41 AM   #5
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Re: Challanging integral

I also have tracks (don't really know what they are called in english), 4 on top of the integral and 0 below. So after i integrate it cant have x as denominator (divided by 0).
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February 24th, 2013, 08:51 AM   #6
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Re: Challanging integral

Quote:
Originally Posted by Realistonia
?sqrt(1+(2/3*x^-1/3)^2)
No point in creating duplicates : viewtopic.php?f=22&t=38531#p157613

Quote:
Originally Posted by Realistonia
Challanging integral
This is not challenging from any direction. It has a very simple elementary (even polynomial, if I am right) form which can easily be seen from u-substitution. Why don't you try some substitutions (have any experience before in solving these problems?) Come on, show some of your efforts, this is not a forum for just solving homework you realize that, right?
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February 24th, 2013, 09:27 AM   #7
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Re: Challanging integral

Well i did 9 on my own, don't know how do do that one. I got x as denominator and divided by 0 error. If you say that i should use substitutions then maybe you could give some pointers on what should i substitute ?
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February 24th, 2013, 12:25 PM   #8
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Re: Challanging integral







now, let ...



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February 27th, 2013, 05:42 AM   #9
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The indefinite integral should be x(1+(2/3*x^(-1/3))^2)^(3/2) + C. If the integration limits are 0 and 4, you can evaluate using a calculator for x = 4.
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