February 24th, 2013, 06:20 AM  #1 
Newbie Joined: Feb 2012 Posts: 14 Thanks: 0  Challenging integral
Hello, Here it is: ?sqrt(1+(2/3*x^1/3)^2) 
February 24th, 2013, 06:33 AM  #2 
Math Team Joined: Aug 2012 From: Sana'a , Yemen Posts: 1,177 Thanks: 44 Math Focus: Theory of analytic functions  Re: Challanging integral
The challenging thing here is trying to read the integral , can you write it in latex ..

February 24th, 2013, 06:57 AM  #3 
Member Joined: Jul 2012 Posts: 60 Thanks: 0 Math Focus: Calculus  Re: Challanging integral First let's make sure we're interpreting the integral correctly. Does your integral look like the one above? 
February 24th, 2013, 08:35 AM  #4 
Newbie Joined: Feb 2012 Posts: 14 Thanks: 0  Re: Challanging integral
Yes, that's how it looks.

February 24th, 2013, 08:41 AM  #5 
Newbie Joined: Feb 2012 Posts: 14 Thanks: 0  Re: Challanging integral
I also have tracks (don't really know what they are called in english), 4 on top of the integral and 0 below. So after i integrate it cant have x as denominator (divided by 0).

February 24th, 2013, 08:51 AM  #6  
Math Team Joined: Mar 2012 From: India, West Bengal Posts: 3,871 Thanks: 86 Math Focus: Number Theory  Re: Challanging integral Quote:
Quote:
 
February 24th, 2013, 09:27 AM  #7 
Newbie Joined: Feb 2012 Posts: 14 Thanks: 0  Re: Challanging integral
Well i did 9 on my own, don't know how do do that one. I got x as denominator and divided by 0 error. If you say that i should use substitutions then maybe you could give some pointers on what should i substitute ?

February 24th, 2013, 12:25 PM  #8 
Math Team Joined: Jul 2011 From: Texas Posts: 2,976 Thanks: 1571  Re: Challanging integral now, let ... 
February 27th, 2013, 05:42 AM  #9 
Global Moderator Joined: Dec 2006 Posts: 20,805 Thanks: 2150 
The indefinite integral should be x(1+(2/3*x^(1/3))^2)^(3/2) + C. If the integration limits are 0 and 4, you can evaluate using a calculator for x = 4.


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