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 September 10th, 2017, 09:31 AM #1 Member   Joined: May 2017 From: Slovenia Posts: 89 Thanks: 0 Osculating circle I need to find the osculating circle of curve p(t) =( 4cos(t)-1; 3t; -4sin(t)) at T(3,0,0). So I have found: t = 0 N(t) = (-cos(t), 0, sin(t)) k(t) = 4/25 r(t) =1/k = 25/4 this is the radius. The center is: p(t) + r(t)N(t) That is: (3,0,0) + 25/4(-1,0,0) = (-13/4, 0, 0) So I have the radius and the center but I'm not sure what to do next. Their answer is : p(phi) = (-13/4-25/4cos(x), 15/4sin(x), -5sin(x))

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