September 9th, 2017, 01:58 PM  #1 
Member Joined: Apr 2017 From: New York Posts: 52 Thanks: 4  Limit question
Hi guys, I have the answers of the question but I didn't understand how? especially numerator part? I know the denominator is factored out and became (x+2)(x1) please look at the question and try to explain me. I appreciate. 
September 9th, 2017, 01:59 PM  #2 
Member Joined: Apr 2017 From: New York Posts: 52 Thanks: 4 
also can you try the same limit with (3x^2ax+a+6)/ (x^2+x2)

September 9th, 2017, 02:19 PM  #3 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,697 Thanks: 977 Math Focus: Elementary mathematics and beyond 
As the denominator is zero at the limiting value (2) we need 2x$^2$ + ax + a + 6 = 0. We then have the indeterminate form 0/0. So, substitute x = 2 into 2x$^2$ + ax + a + 6 = 0 and solve for a. Apply the same method for your other problem. 
September 9th, 2017, 03:00 PM  #4 
Member Joined: Apr 2017 From: New York Posts: 52 Thanks: 4 
This is super helpful. thanks Greg.


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