My Math Forum Limit question

 Calculus Calculus Math Forum

September 9th, 2017, 12:58 PM   #1
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Joined: Apr 2017
From: New York

Posts: 65
Thanks: 6

Limit question

Hi guys,
I have the answers of the question but I didn't understand how? especially numerator part? I know the denominator is factored out and became (x+2)(x-1)

please look at the question and try to explain me.

I appreciate.
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 September 9th, 2017, 12:59 PM #2 Member   Joined: Apr 2017 From: New York Posts: 65 Thanks: 6 also can you try the same limit with (3x^2-ax+a+6)/ (x^2+x-2)
 September 9th, 2017, 01:19 PM #3 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,823 Thanks: 1049 Math Focus: Elementary mathematics and beyond As the denominator is zero at the limiting value (-2) we need 2x$^2$ + ax + a + 6 = 0. We then have the indeterminate form 0/0. So, substitute x = -2 into 2x$^2$ + ax + a + 6 = 0 and solve for a. Apply the same method for your other problem. Thanks from v8archie
 September 9th, 2017, 02:00 PM #4 Member   Joined: Apr 2017 From: New York Posts: 65 Thanks: 6 This is super helpful. thanks Greg. Thanks from greg1313

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