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August 10th, 2017, 03:59 AM   #1
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Please teach me a method

$\displaystyle p(x) = x/2x-3$; find the values of $\displaystyle x$ for which the inverse of $\displaystyle p(x)$ equals to $\displaystyle 2p(x)$
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August 10th, 2017, 04:36 AM   #2
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I'll assume you intended that $p(x) = x/(2x - 3)$.

If the inverse of $p(x)$ is $q(x)$, $x = q(x)/(2q(x) - 3)$, and so $q(x) = 3x/(2x - 1)$.

Now solve $3x/(2x - 1) = 2x/(2x - 3)$.
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