August 10th, 2017, 04:59 AM  #1 
Newbie Joined: Jul 2017 From: Earth Posts: 6 Thanks: 1  Please teach me a method
$\displaystyle p(x) = x/2x3$; find the values of $\displaystyle x$ for which the inverse of $\displaystyle p(x)$ equals to $\displaystyle 2p(x)$

August 10th, 2017, 05:36 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,595 Thanks: 1493 
I'll assume you intended that $p(x) = x/(2x  3)$. If the inverse of $p(x)$ is $q(x)$, $x = q(x)/(2q(x)  3)$, and so $q(x) = 3x/(2x  1)$. Now solve $3x/(2x  1) = 2x/(2x  3)$. 

Tags 
method, teach 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Please teach me how to do this  nbg273  Calculus  6  February 21st, 2017 06:17 AM 
WHAT FERMAT TEACH...  complicatemodulus  Number Theory  3  February 16th, 2014 10:34 AM 
please add me and teach me using MyMathForum !!  MATHEMATICIAN  New Users  12  August 23rd, 2013 03:23 AM 
How to teach yourself...  MattJ81  New Users  7  July 29th, 2011 11:17 PM 
please add me and teach me using MyMathForum !!  MATHEMATICIAN  Calculus  0  December 31st, 1969 04:00 PM 