August 10th, 2017, 04:59 AM  #1 
Newbie Joined: Jul 2017 From: Earth Posts: 6 Thanks: 1  Please teach me a method
$\displaystyle p(x) = x/2x3$; find the values of $\displaystyle x$ for which the inverse of $\displaystyle p(x)$ equals to $\displaystyle 2p(x)$

August 10th, 2017, 05:36 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,250 Thanks: 1439 
I'll assume you intended that $p(x) = x/(2x  3)$. If the inverse of $p(x)$ is $q(x)$, $x = q(x)/(2q(x)  3)$, and so $q(x) = 3x/(2x  1)$. Now solve $3x/(2x  1) = 2x/(2x  3)$. 

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