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 August 9th, 2017, 01:29 AM #1 Member   Joined: May 2017 From: Slovenia Posts: 89 Thanks: 0 Flux of vector field I have F(x,y,z)=(z,0,2) and i need to find the flux through the upper side of the paraboloid z=2-x^2-y^2 1
 August 9th, 2017, 04:29 AM #2 Math Team   Joined: Jan 2015 From: Alabama Posts: 2,922 Thanks: 785 The 'upper side' of the paraboloid is neither z= 1 nor z= 2, it is the paraboloid! The paraboloid $z= 2- x^2- y^2$ has vertex at (0, 0, 2) and opens downward. In order to make it a closed surface, so that you can use the divergence theorem, you would add the plane z= 1. Thanks from ProofOfALifetime and sarajoveska

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