July 28th, 2017, 06:01 AM  #1 
Member Joined: May 2017 From: Slovenia Posts: 87 Thanks: 0  parameterization of curve
I need to parameterize the curve K, which is intersection between P: z=sqrt(x^2+y^2) z<or equal 2 and x=1. And also the curve x^2+y^2z^2=1, x+y+z=0. And I don't have idea where to start. Last edited by skipjack; July 28th, 2017 at 08:18 AM. 
July 28th, 2017, 07:37 AM  #2 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,720 Thanks: 699 
The intersection of the surface $\displaystyle z= \sqrt{x^2+ y^2}$ and the plane x= 1 is, of course, $\displaystyle z= \sqrt{y^2+ 1}$. I would think that x= 1, y= t, $\displaystyle z= \sqrt{t^2+ 1}$ would be an obvious parameterization.

July 29th, 2017, 04:54 AM  #3 
Member Joined: May 2017 From: Slovenia Posts: 87 Thanks: 0  I did that too. But I was not sure about it cos I later got some weird derivatives. Thank you.

July 29th, 2017, 05:28 AM  #4 
Senior Member Joined: Oct 2009 Posts: 142 Thanks: 60  
July 29th, 2017, 06:29 AM  #5 
Member Joined: May 2017 From: Slovenia Posts: 87 Thanks: 0  I used y by mistake it should be t.

July 29th, 2017, 06:59 AM  #6 
Global Moderator Joined: Dec 2006 Posts: 18,037 Thanks: 1394 
Can you provide clear images or type your work?

July 30th, 2017, 12:44 AM  #7 
Member Joined: May 2017 From: Slovenia Posts: 87 Thanks: 0  I hope this is better.

July 30th, 2017, 03:37 AM  #8 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,720 Thanks: 699 
You didn't say anything about differentiating in your first post. What, exactly, does the exercise ask you to do?
Last edited by Country Boy; July 30th, 2017 at 03:39 AM. 
July 30th, 2017, 04:48 AM  #9 
Member Joined: May 2017 From: Slovenia Posts: 87 Thanks: 0  

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