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 July 14th, 2017, 07:29 AM #1 Newbie   Joined: Jul 2017 From: Stuttgart, Germany Posts: 1 Thanks: 0 split multiplication in integral Hi, I've got an equation that looks like this: $\displaystyle G = \int_0^X 4\pi (g-1) r^2 \left( 1-\frac{3r}{4R} + \frac{3r^3}{16R^3} \right) dr$ Now I would like to separate this integral into $\displaystyle G = \int_0^X 4\pi (g-1) r^2 dr + Y$ or $\displaystyle G = \int_0^X 4\pi (g-1) r^2 dr * Y$ where Y does not contain g. Is this possible? Last edited by skipjack; July 14th, 2017 at 10:03 AM. July 14th, 2017, 10:08 AM   #2
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 Originally Posted by Fadabi Hi, I've got an equation that looks like this: $\displaystyle G = \int_0^X 4\pi (g-1) r^2 \left( 1-\frac{3r}{4R} + \frac{3r^3}{16R^3} \right) dr$ Now I would like to separate this integral into $\displaystyle G = \int_0^X 4\pi (g-1) r^2 dr + Y$ or $\displaystyle G = \int_0^X 4\pi (g-1) r^2 dr * Y$ where Y does not contain g. Is this possible?
why not just complete the integral, it's not hard

$\displaystyle G = \int_0^X 4\pi (g-1) r^2 \left( 1-\frac{3r}{4R} + \frac{3r^3}{16R^3} \right) dr =\dfrac{\pi (g-1) X^3 \left(32 R^3-18 R^2 X+3 X^3\right)}{24 R^3}$ July 14th, 2017, 01:08 PM #3 Global Moderator   Joined: May 2007 Posts: 6,834 Thanks: 733 Does g depend on r? If not, direct integration (romsek) works. If g depends on r, what you want is unlikely. Tags integral, integration, multiplication, product, split Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Monox D. I-Fly Math Books 4 April 16th, 2015 11:28 PM Drake Elementary Math 6 August 5th, 2013 06:16 AM Denis Algebra 2 July 31st, 2012 12:18 PM ray Algebra 12 April 26th, 2012 09:30 AM

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