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May 23rd, 2017, 03:08 PM   #1
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u substitution driving me crazy

Nevermind I figured it out
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Last edited by dthiaw; May 23rd, 2017 at 03:22 PM. Reason: solved it
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May 23rd, 2017, 03:59 PM   #2
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for the benefit of future posters looking for problems w/ the FTC ...

$\displaystyle \dfrac{d}{dx} \bigg[\int_{v(x)}^{u(x)} f(t) \, dt\bigg] = f[u(x)] \cdot u'(x)-f[v(x)] \cdot v'(x)$

$\displaystyle \dfrac{d}{dx} \bigg[\int_{\cos{x}}^{\sin{x}} t \, dt\bigg] = \sin{x} \cdot \cos{x} - \cos{x} \cdot (-\sin{x}) = 2\sin{x}\cos{x} = \sin(2x)$
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