May 23rd, 2017, 04:08 PM  #1 
Member Joined: Jan 2017 From: California Posts: 80 Thanks: 8  u substitution driving me crazy
Nevermind I figured it out
Last edited by dthiaw; May 23rd, 2017 at 04:22 PM. Reason: solved it 
May 23rd, 2017, 04:59 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,820 Thanks: 1464 
for the benefit of future posters looking for problems w/ the FTC ... $\displaystyle \dfrac{d}{dx} \bigg[\int_{v(x)}^{u(x)} f(t) \, dt\bigg] = f[u(x)] \cdot u'(x)f[v(x)] \cdot v'(x)$ $\displaystyle \dfrac{d}{dx} \bigg[\int_{\cos{x}}^{\sin{x}} t \, dt\bigg] = \sin{x} \cdot \cos{x}  \cos{x} \cdot (\sin{x}) = 2\sin{x}\cos{x} = \sin(2x)$ 

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