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May 23rd, 2017, 04:08 PM | #1 |
Member Joined: Jan 2017 From: California Posts: 80 Thanks: 8 | u substitution driving me crazy
Nevermind I figured it out
Last edited by dthiaw; May 23rd, 2017 at 04:22 PM. Reason: solved it |
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May 23rd, 2017, 04:59 PM | #2 |
Math Team Joined: Jul 2011 From: Texas Posts: 2,820 Thanks: 1464 |
for the benefit of future posters looking for problems w/ the FTC ... $\displaystyle \dfrac{d}{dx} \bigg[\int_{v(x)}^{u(x)} f(t) \, dt\bigg] = f[u(x)] \cdot u'(x)-f[v(x)] \cdot v'(x)$ $\displaystyle \dfrac{d}{dx} \bigg[\int_{\cos{x}}^{\sin{x}} t \, dt\bigg] = \sin{x} \cdot \cos{x} - \cos{x} \cdot (-\sin{x}) = 2\sin{x}\cos{x} = \sin(2x)$ |
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