My Math Forum Calculus acceleration range of positive values??? help!

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 May 16th, 2017, 10:14 AM #1 Newbie   Joined: May 2017 From: uk Posts: 5 Thanks: 0 Calculus acceleration range of positive values??? help! A particle starting from rest moves with velocity v ms^-1 where v=3t(t-4) find the range of values of t for which acceleration is positive. 3t-4*t is this the start? Then plug in values? Felling very list with what the question is asking.
 May 16th, 2017, 10:36 AM #2 Senior Member     Joined: Sep 2015 From: CA Posts: 1,202 Thanks: 613 You're missing the point of the question. You need to find the derivative of the velocity function you are given to obtain the acceleration. Then find for what values of t the derivative is positive. $a(t) = \dfrac{d}{dt} v(t)$ $\text{Find }t \ni a(t)>0$ Thanks from DomB
 May 16th, 2017, 11:21 AM #3 Newbie   Joined: May 2017 From: uk Posts: 5 Thanks: 0 Great Thanks, I think i'm getting it now..... more practice needed

 Tags acceleration, calculus, positive, range, values

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