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May 16th, 2017, 10:14 AM  #1 
Newbie Joined: May 2017 From: uk Posts: 5 Thanks: 0  Calculus acceleration range of positive values??? help!
A particle starting from rest moves with velocity v ms^1 where v=3t(t4) find the range of values of t for which acceleration is positive. 3t4*t is this the start? Then plug in values? Felling very list with what the question is asking. 
May 16th, 2017, 10:36 AM  #2 
Senior Member Joined: Sep 2015 From: CA Posts: 1,202 Thanks: 613 
You're missing the point of the question. You need to find the derivative of the velocity function you are given to obtain the acceleration. Then find for what values of t the derivative is positive. $a(t) = \dfrac{d}{dt} v(t)$ $\text{Find }t \ni a(t)>0$ 
May 16th, 2017, 11:21 AM  #3 
Newbie Joined: May 2017 From: uk Posts: 5 Thanks: 0 
Great Thanks, I think i'm getting it now..... more practice needed 

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acceleration, calculus, positive, range, values 
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