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May 16th, 2017, 10:14 AM   #1
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Calculus acceleration range of positive values??? help!

A particle starting from rest moves with velocity v ms^-1 where v=3t(t-4) find the range of values of t for which acceleration is positive.

3t-4*t is this the start? Then plug in values? Felling very list with what the question is asking.
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May 16th, 2017, 10:36 AM   #2
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You're missing the point of the question.

You need to find the derivative of the velocity function you are given to obtain the acceleration. Then find for what values of t the derivative is positive.

$a(t) = \dfrac{d}{dt} v(t)$

$\text{Find }t \ni a(t)>0$
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May 16th, 2017, 11:21 AM   #3
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Great Thanks, I think i'm getting it now..... more practice needed
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