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May 15th, 2017, 02:43 AM   #1
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plz help me to solve this problem

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May 15th, 2017, 03:12 AM   #2
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Remembering the trig identity , I would let . Then so the integral becomes .

Now you should remember that is defined as so that integral is the same as . That has cosine to an odd power and there is a standard way of treating such integrals- multiply both numerator and denominator by to get . Let so that and the integral becomes which can be done by "partial fractions".

Last edited by Country Boy; May 15th, 2017 at 03:15 AM.
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May 15th, 2017, 03:51 AM   #3
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Quote:
Originally Posted by senawy View Post
I do not believe this function has an elementary, closed-form antiderivative.

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May 15th, 2017, 05:07 AM   #4
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my reply

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Originally Posted by Country Boy View Post
Remembering the trig identity , I would let . Then so the integral becomes .

Now you should remember that is defined as so that integral is the same as . That has cosine to an odd power and there is a standard way of treating such integrals- multiply both numerator and denominator by to get . Let so that and the integral becomes which can be done by "partial fractions".
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