My Math Forum I dont understand how this is the answer deriative

 Calculus Calculus Math Forum

 May 9th, 2017, 11:54 AM #1 Member   Joined: Feb 2017 From: henderson Posts: 36 Thanks: 0 I dont understand how this is the answer deriative tan^2(2+3x) I have no clue how they get (6tan)(2+3x)(cos^-2)(2+3x) I used chain and what I got is 6sec^2(2+3x)
 May 9th, 2017, 12:05 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,923 Thanks: 1123 Math Focus: Elementary mathematics and beyond $$(\tan^2(2+3x))'=2\cdot\tan(2+3x)\cdot\sec^2(2+3x )\cdot3$$ Does that help?
May 9th, 2017, 12:55 PM   #3
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 Originally Posted by greg1313 $$(\tan^2(2+3x))'=2\cdot\tan(2+3x)\cdot\sec^2(2+3x )\cdot3$$ Does that help?
how do they get cos?

 May 9th, 2017, 01:01 PM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,923 Thanks: 1123 Math Focus: Elementary mathematics and beyond Do you know what $\sec(x)$ is in terms of $\cos(x)$?

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