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May 9th, 2017, 12:17 PM   #1
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Question confused on derivative rules

so I have ln(cos(w-1))

dont I use chain rule
can somebody do a step by step?
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May 9th, 2017, 12:24 PM   #2
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Yes, you do use the chain rule.

What is the chain rule? And how do you imagine that it might be applied here?
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May 9th, 2017, 12:35 PM   #3
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Quote:
Originally Posted by v8archie View Post
Yes, you do use the chain rule.

What is the chain rule? And how do you imagine that it might be applied here?
f(g(x)) = f'(g(x))*g'(x)

I get 1/cos(w-1) but Im unsure what to do next im confused on it
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May 9th, 2017, 12:51 PM   #4
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Quote:
Originally Posted by Bobbyjoe View Post
f(g(x)) = f'(g(x))*g'(x)

I get 1/cos(w-1) but Im unsure what to do next im confused on it
$g(w) = \cos(w-1)$

$g^\prime(w) = -\sin(w-1)$

$\dfrac{d}{dw} \ln(\cos(w-1)) = -\dfrac{\sin(w-1)}{\cos(w-1)} = -\tan(w-1)=\tan(1-w)$
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