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April 22nd, 2017, 09:47 AM   #1
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Extremum values

Find extremum value of $\displaystyle \;$$\displaystyle y=\frac{1}{2} x^2 +cosx$
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April 22nd, 2017, 10:19 AM   #2
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What is the general method for finding extrema of differentiable functions?

What did you get when you tried that?
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April 22nd, 2017, 11:49 AM   #3
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You are not going to be able to find a simple numerical solution to , you will need some sort of numerical solution.
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April 22nd, 2017, 01:05 PM   #4
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Quote:
Originally Posted by Country Boy View Post
You are not going to be able to find a simple numerical solution to , you will need some sort of numerical solution.
In general I'd agree but here $x=0$ does the job nicely and is in fact the only solution.
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