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 April 22nd, 2017, 10:47 AM #1 Senior Member   Joined: Dec 2015 From: Earth Posts: 177 Thanks: 23 Extremum values Find extremum value of $\displaystyle \;$$\displaystyle y=\frac{1}{2} x^2 +cosx$
 April 22nd, 2017, 11:19 AM #2 Senior Member   Joined: May 2016 From: USA Posts: 823 Thanks: 335 What is the general method for finding extrema of differentiable functions? What did you get when you tried that?
 April 22nd, 2017, 12:49 PM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 2,821 Thanks: 750 You are not going to be able to find a simple numerical solution to $x= sin(x)$, you will need some sort of numerical solution.
April 22nd, 2017, 02:05 PM   #4
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Quote:
 Originally Posted by Country Boy You are not going to be able to find a simple numerical solution to $x= sin(x)$, you will need some sort of numerical solution.
In general I'd agree but here $x=0$ does the job nicely and is in fact the only solution.

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