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April 11th, 2017, 07:20 PM   #1
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Find the area of the region between the curve



I've asked a similar problem on here already (still waiting for a reply) but it has something new to this one, the horizontal part of it
isnt it just 0?
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April 11th, 2017, 07:38 PM   #2
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Hi Bobbyjoe and welcome to the forum. You need to evaluate

$$8\int_2^4\ln(x)\,dx$$

Can you proceed?
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April 11th, 2017, 07:42 PM   #3
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Originally Posted by greg1313 View Post
Hi Bobbyjoe and welcome to the forum. You need to evaluate

$$8\int_2^4\ln(x)\,dx$$

Can you proceed?
so am I not suppose to acknowledged the horizontal axis?
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April 11th, 2017, 07:51 PM   #4
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The definite integral I gave will give the area between $8\ln(x)$ and the $x$-axis. The length of the curve of $8\ln(x)$ is above $y=0$ for the interval $[2,4]$.
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April 11th, 2017, 07:53 PM   #5
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The definite integral I gave will give the area between $8\ln(x)$ and the $x$-axis. The length of the curve of $8\ln(x)$ is above $y=0$ for the interval $[2,4]$.
Oh okay, I think I understand! Thank you so much!
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April 12th, 2017, 04:53 AM   #6
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so am I not suppose to acknowledged the horizontal axis?
The horizontal axis is y= 0. You are integrating 8 ln(x)- 0= 8ln(x).
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