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 April 11th, 2017, 07:07 PM #1 Member   Joined: Feb 2017 From: henderson Posts: 36 Thanks: 0 Find the area of the region under Guys, I need help understanding how to do this problem. I've looked online and in my textbooks and I have yet to find a problem just like this, so I need help. Thank you! Last edited by skipjack; April 12th, 2017 at 05:26 AM.
 April 11th, 2017, 07:46 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,814 Thanks: 1046 Math Focus: Elementary mathematics and beyond Hi. You want $$\int_0^3e^x-1\,dx$$ Does that make sense? (Hint: make a sketch of $e^x$ and the line $y=1$).
April 11th, 2017, 07:50 PM   #3
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Quote:
 Originally Posted by greg1313 Hi. You want $$\int_0^3e^x-1\,dx$$ Does that make sense? (Hint: make a sketch of $e^x$ and the line $y=1$).
so why did you move the 1? like can you explain how you know how to set up the problem?

 April 12th, 2017, 04:58 AM #4 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,188 Thanks: 871 What do you mean by "move the 1"? Where did he move it from? To "find the area between two curves", y= f(x), and y= g(x), between x= a and x= b, if f(x)> g(x) in that region, integrate $\displaystyle \int_a^b f(x)- g(x) dx$. Here $\displaystyle f(x)= e^x$ and $\displaystyle g(x)= 1$ so the area is given by $\displaystyle \int_0^3 e^x- 1 dx$ Last edited by skipjack; April 12th, 2017 at 05:28 AM.

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