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April 11th, 2017, 07:07 PM   #1
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Find the area of the region under



Guys, I need help understanding how to do this problem. I've looked online and in my textbooks and I have yet to find a problem just like this, so I need help. Thank you!

Last edited by skipjack; April 12th, 2017 at 05:26 AM.
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April 11th, 2017, 07:46 PM   #2
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Hi. You want

$$\int_0^3e^x-1\,dx$$

Does that make sense? (Hint: make a sketch of $e^x$ and the line $y=1$).
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April 11th, 2017, 07:50 PM   #3
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Quote:
Originally Posted by greg1313 View Post
Hi. You want

$$\int_0^3e^x-1\,dx$$

Does that make sense? (Hint: make a sketch of $e^x$ and the line $y=1$).
so why did you move the 1? like can you explain how you know how to set up the problem?
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April 12th, 2017, 04:58 AM   #4
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What do you mean by "move the 1"? Where did he move it from?

To "find the area between two curves", y= f(x), and y= g(x), between x= a and x= b, if f(x)> g(x) in that region, integrate $\displaystyle \int_a^b f(x)- g(x) dx$.

Here $\displaystyle f(x)= e^x$ and $\displaystyle g(x)= 1$ so the area is given by $\displaystyle \int_0^3 e^x- 1 dx$

Last edited by skipjack; April 12th, 2017 at 05:28 AM.
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