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April 8th, 2017, 07:37 PM  #1 
Member Joined: Oct 2015 From: Antarctica Posts: 90 Thanks: 0  Volume of Intersection of Two Cylinders
Given the cylinders:
Set up and evaluate the triple integral that gives the volume of their intersection. I cannot figure out what the bounds on my integrals should be and I'm not even sure which coordinate system to use to solve this. Can anybody help? 
April 9th, 2017, 12:29 PM  #2 
Senior Member Joined: Sep 2015 From: Southern California, USA Posts: 1,500 Thanks: 757 
If you look at this carefully you'll find that cross sections parallel to the xy plane have identical limits $x:(\sqrt{1z^2},\sqrt{1z^2})$ $y:(\sqrt{1z^2},\sqrt{1z^2})$ thus the volume of a cross section with infinitesimal thickness is $dV = (2\sqrt{1z^2})(2\sqrt{1z^2}) ~dz= 4(1z^2)~dz$ $V = \displaystyle \int_{1}^1 ~4 (1z^2)~dz = \dfrac{16}{3}$ If you need to cast this as a triple integral just write $V = \displaystyle \int_{1}^1 \int_{\sqrt{1z^2}}^{\sqrt{1z^2}}\int_{\sqrt{1z^2}}^{\sqrt{1z^2}} ~dx~dy~dz$ 

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cylinders, intersection, volume 
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