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March 19th, 2017, 06:49 PM  #1 
Member Joined: Feb 2017 From: henderson Posts: 36 Thanks: 0  Find the tangent line approximation (#3)
Find the tangent line approximation for f(x) = √(15 + x) near 0
Last edited by skipjack; March 19th, 2017 at 11:06 PM. 
March 19th, 2017, 07:26 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,089 Thanks: 1085 
you should be able to do this given you did most of the other one. $f(x) = \sqrt{15+x},~f(0)=\sqrt{15}$ $f'(x) = \dfrac{1}{2\sqrt{15+x}},~f'(0) = \dfrac{1}{2\sqrt{15}}$ $f(x) \approx \dfrac {1}{2\sqrt{15}}x +\sqrt{15}$ 
March 19th, 2017, 08:25 PM  #3 
Senior Member Joined: Aug 2012 Posts: 1,998 Thanks: 569 
Should there be a daily limit on domyhomework posts from new handles? Am I rude or inappropriate to ask? OP nothing personal, you'd not doing anything a lot of other people do, just more of it.

March 19th, 2017, 11:35 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 19,502 Thanks: 1739 
That would be arbitrary. Bobbyjoe has read what to do, but is making careless errors, and possibly needs a better understanding. That's a common situation.

March 20th, 2017, 12:33 AM  #5 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,634 Thanks: 567 Math Focus: Yet to find out.  Even if there was, a bored helper would likely come along and do it anyway.


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approximation, find, line, tangent 
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