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March 19th, 2017, 06:49 PM   #1
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Question Find the tangent line approximation (#3)

Find the tangent line approximation for f(x) = √(15 + x) near 0

Last edited by skipjack; March 19th, 2017 at 11:06 PM.
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March 19th, 2017, 07:26 PM   #2
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you should be able to do this given you did most of the other one.

$f(x) = \sqrt{15+x},~f(0)=\sqrt{15}$

$f'(x) = \dfrac{1}{2\sqrt{15+x}},~f'(0) = \dfrac{1}{2\sqrt{15}}$

$f(x) \approx \dfrac {1}{2\sqrt{15}}x +\sqrt{15}$
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March 19th, 2017, 08:25 PM   #3
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Should there be a daily limit on do-my-homework posts from new handles? Am I rude or inappropriate to ask? OP nothing personal, you'd not doing anything a lot of other people do, just more of it.
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March 19th, 2017, 11:35 PM   #4
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That would be arbitrary. Bobbyjoe has read what to do, but is making careless errors, and possibly needs a better understanding. That's a common situation.
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March 20th, 2017, 12:33 AM   #5
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Quote:
Originally Posted by Maschke View Post
Should there be a daily limit on do-my-homework posts from new handles? Am I rude or inappropriate to ask? OP nothing personal, you'd not doing anything a lot of other people do, just more of it.
Even if there was, a bored helper would likely come along and do it anyway.
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