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March 2nd, 2017, 02:54 AM  #1 
Newbie Joined: Mar 2017 From: US Posts: 2 Thanks: 0  Hi...I'm a new member here...I would be glad if anyone could see the following is cor Shenaya Perera 
March 2nd, 2017, 05:17 AM  #2 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,337 Thanks: 587 
The left side of that is rather blurry and hard to read but I believe you have You then divide both numerator and denominator by , dividing each term in both numerator and denominator by that. Yes, since the numerator is a finite sum, you can do that. Each term in the numerator is getting . Now, again because the numerator is a finite sum with 2017 terms, no matter what x is, you can take the limit in each term as x goes to infinity. Of course, each fraction, with x in the denominator, goes to 0 leaving the sum of 2017 "1"s in the numerator while the denominator goes to 1. The result is 2017. 
March 2nd, 2017, 05:24 AM  #3  
Newbie Joined: Mar 2017 From: US Posts: 2 Thanks: 0  Quote:
Shenaya Perera  

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