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February 23rd, 2017, 06:29 AM   #1
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Calculus (Surface Area of Solid Revolution)

How do you integrate and graph this?
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February 23rd, 2017, 06:40 AM   #2
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y=1/4 x^3 , 0 <= X <= 3

This is the given
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February 23rd, 2017, 06:53 AM   #3
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NVM I got it
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February 23rd, 2017, 08:02 AM   #4
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Quote:
Originally Posted by SirSam View Post
y=1/4 x^3 , 0 <= X <= 3

This is the given


the integral in the image represents the surface area of the solid formed by rotating the curve $y=\dfrac{1}{3}x^3$ about the x-axis over the interval $[0,3]$.

... is there a typo in your given function?
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