My Math Forum Calculus (Surface Area of Solid Revolution)

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February 23rd, 2017, 06:29 AM   #1
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Calculus (Surface Area of Solid Revolution)

How do you integrate and graph this?
Attached Images
 gdsgfsdfg.jpg (2.6 KB, 7 views)

 February 23rd, 2017, 06:40 AM #2 Newbie   Joined: Feb 2017 From: QC Posts: 3 Thanks: 0 y=1/4 x^3 , 0 <= X <= 3 This is the given
 February 23rd, 2017, 06:53 AM #3 Newbie   Joined: Feb 2017 From: QC Posts: 3 Thanks: 0 NVM I got it
February 23rd, 2017, 08:02 AM   #4
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Quote:
 Originally Posted by SirSam y=1/4 x^3 , 0 <= X <= 3 This is the given

the integral in the image represents the surface area of the solid formed by rotating the curve $y=\dfrac{1}{3}x^3$ about the x-axis over the interval $[0,3]$.

... is there a typo in your given function?

 Tags area, calculus, revolution, solid, surface

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