My Math Forum Struggling to understand this integration and logs..

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 February 13th, 2017, 11:28 AM #1 Newbie   Joined: Oct 2014 From: england Posts: 23 Thanks: 0 Struggling to understand this integration and logs.. Hi all, I have a question which I've started. I'm a bit stumped. Solve x=0 y=1/2 1/y + 1/(1-y) dy = 1 dx lny - ln(1-y) = x +c c=0 This is where I'm unsure how to proceed. Is it log law? ln y/(1-y) = x then take e's to both side? y/(1-y) =e^x Thanks for any advice. Last edited by skipjack; February 15th, 2017 at 12:34 PM.
 February 13th, 2017, 02:02 PM #2 Global Moderator   Joined: May 2007 Posts: 6,770 Thanks: 700 Solve what expression? Solve for what?
February 13th, 2017, 02:04 PM   #3
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Quote:
 y/(1-y) =e^x
yes ... now solve for $y$ in terms of $x$

February 15th, 2017, 09:03 AM   #4
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Quote:
 Originally Posted by mathman Solve what expression? Solve for what?
I presume that nicevans1 problem was "solve the differential equation
(1/y+ 1/(1-y)) dy = 1 dx with the initial condition y(0)= 1/2".

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