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February 9th, 2017, 10:45 PM  #1 
Member Joined: Nov 2014 From: SG Posts: 55 Thanks: 1  How to inverse z transform this equation?
Given Y(z) / U(z) = ( 5z(+0.6) ) / (z^2z+0.41) Find the response y(k) to a unit step change in u(k) My answer: Since it said unit step change of u(k) , U(z) = 1 / (1z^1) Hence, Y(z) = ( 5z(+0.6) ) / (z^2z+0.41) * 1 / (1z^1) = ( 5z(+0.6) ) / (z^2z+0.41) * z/(z1) By partial fraction I will get (814.5122z)/(z^2z+0.41) + 19.512z/(z1) How do I z transform this > 814.5122z)/(z^2z+0.41) ?? I use wolframlpha and it gives me something I am not sure of inverse Z transform calculator ((814z)/(z^2z+0.41))  WolframAlpha Results 
February 9th, 2017, 11:28 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,553 Thanks: 1403 
what does $(5z(+0.6))$ mean?

February 10th, 2017, 12:18 AM  #3 
Member Joined: Nov 2014 From: SG Posts: 55 Thanks: 1  

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equation, inverse, transform 
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