My Math Forum How to inverse z transform this equation?

 Calculus Calculus Math Forum

 February 9th, 2017, 10:45 PM #1 Member     Joined: Nov 2014 From: SG Posts: 55 Thanks: 1 How to inverse z transform this equation? Given Y(z) / U(z) = ( 5z(+0.6) ) / (z^2-z+0.41) Find the response y(k) to a unit step change in u(k) My answer: Since it said unit step change of u(k) , U(z) = 1 / (1-z^-1) Hence, Y(z) = ( 5z(+0.6) ) / (z^2-z+0.41) * 1 / (1-z^-1) = ( 5z(+0.6) ) / (z^2-z+0.41) * z/(z-1) By partial fraction I will get (8-14.5122z)/(z^2-z+0.41) + 19.512z/(z-1) How do I z transform this --> 8-14.5122z)/(z^2-z+0.41) ?? I use wolframlpha and it gives me something I am not sure of inverse Z transform calculator ((8-14z)/(z^2-z+0.41)) - Wolfram|Alpha Results
 February 9th, 2017, 11:28 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,553 Thanks: 1403 what does $(5z(+0.6))$ mean?
February 10th, 2017, 12:18 AM   #3
Member

Joined: Nov 2014
From: SG

Posts: 55
Thanks: 1

Quote:
 Originally Posted by romsek what does $(5z(+0.6))$ mean?

It should be 5(z+0.6) . I accidentally miss out the z. sorry

 Tags equation, inverse, transform

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post szz Applied Math 0 December 16th, 2015 01:03 PM Bkalma Calculus 1 May 6th, 2014 07:08 PM defunktlemon Real Analysis 1 April 14th, 2012 02:19 PM timh Applied Math 1 June 7th, 2010 06:44 PM kalimat Applied Math 0 November 1st, 2009 10:12 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top