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February 9th, 2017, 11:45 PM   #1
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How to inverse z transform this equation?

Given

Y(z) / U(z) = ( 5z(+0.6) ) / (z^2-z+0.41)

Find the response y(k) to a unit step change in u(k)

My answer:

Since it said unit step change of u(k) , U(z) = 1 / (1-z^-1)

Hence,

Y(z) = ( 5z(+0.6) ) / (z^2-z+0.41) * 1 / (1-z^-1)

= ( 5z(+0.6) ) / (z^2-z+0.41) * z/(z-1)

By partial fraction

I will get

(8-14.5122z)/(z^2-z+0.41) + 19.512z/(z-1)

How do I z transform this --> 8-14.5122z)/(z^2-z+0.41) ??
I use wolframlpha and it gives me something I am not sure of
inverse Z transform calculator ((8-14z)/(z^2-z+0.41)) - Wolfram|Alpha Results
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February 10th, 2017, 12:28 AM   #2
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what does $(5z(+0.6))$ mean?
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February 10th, 2017, 01:18 AM   #3
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Quote:
Originally Posted by romsek View Post
what does $(5z(+0.6))$ mean?
My bad.

It should be 5(z+0.6) . I accidentally miss out the z. sorry
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