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 February 9th, 2017, 10:45 PM #1 Member   Joined: Nov 2014 From: SG Posts: 55 Thanks: 1 How to inverse z transform this equation? Given Y(z) / U(z) = ( 5z(+0.6) ) / (z^2-z+0.41) Find the response y(k) to a unit step change in u(k) My answer: Since it said unit step change of u(k) , U(z) = 1 / (1-z^-1) Hence, Y(z) = ( 5z(+0.6) ) / (z^2-z+0.41) * 1 / (1-z^-1) = ( 5z(+0.6) ) / (z^2-z+0.41) * z/(z-1) By partial fraction I will get (8-14.5122z)/(z^2-z+0.41) + 19.512z/(z-1) How do I z transform this --> 8-14.5122z)/(z^2-z+0.41) ?? I use wolframlpha and it gives me something I am not sure of inverse Z transform calculator ((8-14z)/(z^2-z+0.41)) - Wolfram|Alpha Results February 9th, 2017, 11:28 PM #2 Senior Member   Joined: Sep 2015 From: USA Posts: 2,553 Thanks: 1403 what does $(5z(+0.6))$ mean? February 10th, 2017, 12:18 AM   #3
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Joined: Nov 2014
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Quote:
 Originally Posted by romsek what does $(5z(+0.6))$ mean?

It should be 5(z+0.6) . I accidentally miss out the z. sorry Tags equation, inverse, transform Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post szz Applied Math 0 December 16th, 2015 01:03 PM Bkalma Calculus 1 May 6th, 2014 07:08 PM defunktlemon Real Analysis 1 April 14th, 2012 02:19 PM timh Applied Math 1 June 7th, 2010 06:44 PM kalimat Applied Math 0 November 1st, 2009 10:12 AM

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