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January 5th, 2017, 01:44 AM   #1
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Internation problem! Need help

What will be the integration of
INT[min(sinx,cosx)] Whose Limit is 0 to π
What is min(sinx,cosx) How can I solve this?
And I have one more question
INT[min|x-3|-|x+2|]
Limit is -2 to 2
Plz help!
Thanks from geometry
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January 5th, 2017, 02:56 AM   #2
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You can assume that min(x, y) denotes the minimum of the two values,
so that min(sin(x), cos(x)) will be sin(x) for x ∈ [0, $\pi$/4] and cos(x) for x ∈ [$\pi$/4, $\pi$].

The second question appears to be mistyped.
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January 5th, 2017, 05:22 AM   #3
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Could you please solve it completely?

Last edited by skipjack; January 5th, 2017 at 07:38 AM.
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January 5th, 2017, 05:44 AM   #4
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Are you saying you do not know how to integrate sin(x) and cos(x)? If so, you had better talk to your teacher about this.
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January 5th, 2017, 09:14 PM   #5
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@Country boy
Well I know how to integrate sinx and cosx but I was doing this separately and was not adding them so I didn't get the ans and that's why I asked him to solve completely.
Anyways Thanks!
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January 6th, 2017, 04:45 AM   #6
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Skipjack told you that "min(sin(x), cos(x)) will be sin(x) for x ∈ [0, π/4] and cos(x) for x ∈ [π/4,π]." Integrate that!
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January 6th, 2017, 06:51 AM   #7
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I did this already and got my ans.
I was saying something else but let it be!
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