My Math Forum Internation problem! Need help
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 Calculus Calculus Math Forum

 January 5th, 2017, 01:44 AM #1 Newbie   Joined: Jan 2017 From: India Posts: 12 Thanks: 1 Internation problem! Need help What will be the integration of INT[min(sinx,cosx)] Whose Limit is 0 to π What is min(sinx,cosx) How can I solve this? And I have one more question INT[min|x-3|-|x+2|] Limit is -2 to 2 Plz help! Thanks from geometry
 January 5th, 2017, 02:56 AM #2 Global Moderator   Joined: Dec 2006 Posts: 17,201 Thanks: 1291 You can assume that min(x, y) denotes the minimum of the two values, so that min(sin(x), cos(x)) will be sin(x) for x ∈ [0, $\pi$/4] and cos(x) for x ∈ [$\pi$/4, $\pi$]. The second question appears to be mistyped.
 January 5th, 2017, 05:22 AM #3 Newbie   Joined: Jan 2017 From: India Posts: 12 Thanks: 1 Could you please solve it completely? Last edited by skipjack; January 5th, 2017 at 07:38 AM.
 January 5th, 2017, 05:44 AM #4 Math Team   Joined: Jan 2015 From: Alabama Posts: 2,489 Thanks: 630 Are you saying you do not know how to integrate sin(x) and cos(x)? If so, you had better talk to your teacher about this.
 January 5th, 2017, 09:14 PM #5 Newbie   Joined: Jan 2017 From: India Posts: 12 Thanks: 1 @Country boy Well I know how to integrate sinx and cosx but I was doing this separately and was not adding them so I didn't get the ans and that's why I asked him to solve completely. Anyways Thanks!
 January 6th, 2017, 04:45 AM #6 Math Team   Joined: Jan 2015 From: Alabama Posts: 2,489 Thanks: 630 Skipjack told you that "min(sin(x), cos(x)) will be sin(x) for x ∈ [0, π/4] and cos(x) for x ∈ [π/4,π]." Integrate that!
 January 6th, 2017, 06:51 AM #7 Newbie   Joined: Jan 2017 From: India Posts: 12 Thanks: 1 I did this already and got my ans. I was saying something else but let it be!

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