January 5th, 2017, 01:44 AM  #1 
Newbie Joined: Jan 2017 From: India Posts: 12 Thanks: 1  Internation problem! Need help
What will be the integration of INT[min(sinx,cosx)] Whose Limit is 0 to π What is min(sinx,cosx) How can I solve this? And I have one more question INT[minx3x+2] Limit is 2 to 2 Plz help! 
January 5th, 2017, 02:56 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 17,201 Thanks: 1291 
You can assume that min(x, y) denotes the minimum of the two values, so that min(sin(x), cos(x)) will be sin(x) for x ∈ [0, $\pi$/4] and cos(x) for x ∈ [$\pi$/4, $\pi$]. The second question appears to be mistyped. 
January 5th, 2017, 05:22 AM  #3 
Newbie Joined: Jan 2017 From: India Posts: 12 Thanks: 1 
Could you please solve it completely?
Last edited by skipjack; January 5th, 2017 at 07:38 AM. 
January 5th, 2017, 05:44 AM  #4 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,489 Thanks: 630 
Are you saying you do not know how to integrate sin(x) and cos(x)? If so, you had better talk to your teacher about this.

January 5th, 2017, 09:14 PM  #5 
Newbie Joined: Jan 2017 From: India Posts: 12 Thanks: 1 
@Country boy Well I know how to integrate sinx and cosx but I was doing this separately and was not adding them so I didn't get the ans and that's why I asked him to solve completely. Anyways Thanks! 
January 6th, 2017, 04:45 AM  #6 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,489 Thanks: 630 
Skipjack told you that "min(sin(x), cos(x)) will be sin(x) for x ∈ [0, π/4] and cos(x) for x ∈ [π/4,π]." Integrate that!

January 6th, 2017, 06:51 AM  #7 
Newbie Joined: Jan 2017 From: India Posts: 12 Thanks: 1 
I did this already and got my ans. I was saying something else but let it be! 