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December 16th, 2016, 11:54 AM   #11
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What you have written is just the derivative of $f(x) = \sqrt{x}$ for $x = 3$. L'Hospital's rule is not only unncessary, it doesn't even apply since knowing it is applicable is equivalent to already knowing this limit. In any case, just compute $f'(3) = \frac{1}{2\sqrt{3}}$
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December 16th, 2016, 02:08 PM   #12
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Originally Posted by Country Boy View Post
Is this $\displaystyle \frac{(1+ x)^1}{x}$ . . . ?

Yes, it is.

If the first, then the limit is simply $\displaystyle \frac{2^1}{1}= 2$.

Yes, it would be.
SlayedByMath, please start a new thread for each new problem, and put grouping symbols around
exponents where necessary, as in:

Lim x -> 1 (1 + x)^(1/x)


Last edited by Math Message Board tutor; December 16th, 2016 at 02:15 PM.
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