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December 13th, 2016, 05:23 PM   #11
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Quote:
 Originally Posted by aneka so... a(t) = (-1/(t+1)^2 , -1/2(x+4)^3/2 , 2 ) ??? ??
Close enough that the one thing you got wrong is probably just a typo. The y component is $\displaystyle -\frac{1}{2} (t + 4)^{-3/2}$

Good job.

Now how about that cosine formula? The angle between any two vectors v and a is given by the dot product $\displaystyle v \cdot a = |v|~|a| ~ cos( \theta )$. Can you find $\displaystyle \theta$?

-Dan

Last edited by topsquark; December 13th, 2016 at 05:27 PM.

 December 14th, 2016, 01:26 AM #12 Newbie   Joined: Dec 2016 From: Hungary Posts: 12 Thanks: 0 hellooo ?
 December 14th, 2016, 05:34 AM #13 Math Team     Joined: May 2013 From: The Astral plane Posts: 2,200 Thanks: 898 Math Focus: Wibbly wobbly timey-wimey stuff. Hello and good morning! How are you coming along with the cosine formula? -Dan

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