My Math Forum Need Help with chain rule

 Calculus Calculus Math Forum

 November 30th, 2016, 02:34 AM #1 Member   Joined: Sep 2013 Posts: 83 Thanks: 0 So I took this off a course book I'm reading on microeconomics note: $\displaystyle {x_1} = \phi (\bar z + {y^h} - x_2^h)$ I tried using the chain rule: $\displaystyle {{dU} \over {dz}} = {{dU} \over {d{x_1}}}{{d{x_1}} \over {dz}} + {{dU} \over {d{x_2}}}{{d{x_2}} \over {dz}}$ where I got the same expression EXCEPT for the first term, so I don't understand where the (-)sign come from: $\displaystyle - U_1^h({x_1},x_2^h)$ Last edited by skipjack; November 30th, 2016 at 06:15 AM.
 November 30th, 2016, 08:35 AM #2 Member   Joined: Sep 2013 Posts: 83 Thanks: 0 update: So instead of applying the normal chain rule, since: \displaystyle \eqalign{ & z = U({x_1},x_2^h) \cr & {x_1} = g({x_2}) \cr & {{dz} \over {d{x_2}}} = {{\partial f} \over {\partial {x_1}}}{{d{x_1}} \over {d{x_2}}} + {{\partial f} \over {\partial {x_2}}}{{d{x_2}} \over {d{x_2}}} = {{\partial f} \over {\partial {x_1}}}{{d{x_1}} \over {d{x_2}}} + {{\partial f} \over {\partial {x_2}}} \cr} , since $\displaystyle {x_1}$ is function of $\displaystyle x_2^h$. This seems to yield the correct expression, or maybe I've missed something ? Last edited by Ku5htr1m; November 30th, 2016 at 08:41 AM.
 November 30th, 2016, 03:55 PM #3 Member   Joined: Sep 2013 Posts: 83 Thanks: 0 This is from F.A.Cowell - Microeconomics - Principles and Analysis p.452-453

 Tags chain, rule

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post ungeheuer Calculus 1 July 30th, 2013 05:10 PM unwisetome3 Calculus 4 October 19th, 2012 01:21 PM Peter1107 Calculus 1 September 8th, 2011 10:25 AM tarakae Calculus 1 March 13th, 2009 11:06 AM Falxix Calculus 3 May 3rd, 2008 11:33 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top