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November 10th, 2016, 05:19 PM  #1 
Member Joined: Aug 2016 From: South Korea Posts: 54 Thanks: 0  Help!! How do I find table of values for undetermined Limit?
The given problem is 3x^2 + 2x/x , x> 0 and the only ans. Ive got is 0/0 How do I make Table of values for this and how can I determine if the limit exists or not?? 
November 10th, 2016, 05:45 PM  #2 
Senior Member Joined: Sep 2013 From: Earth Posts: 827 Thanks: 36 
Is this your question given? $\displaystyle \lim_{x\rightarrow 0} 3x^2+\frac{2x}{x}$ If this is the question given, then the answer is 2. 
November 11th, 2016, 03:28 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 
By "table of values", I think you mean just a table of values of your function for x close to 0. If you mean as jiasyuen suggested (which is what you wrote) then when x= 1, y= 3+ 2/2= 4 x= 1/2, y= (3/4)+ 1/(1/2)= 2.75 x= 1/4, y= (3/16)+ (1/2)/(1/4)= 2.1875 etc. If you mean, as I suspect, [tex]\frac{3x^2+ 2x}{x} then x= 1, y= (3+ 2)/1= 5 x= 1/2, y= (3/4+ 1)/1/2= 2(7/4)= 7/2= 3.5 x= 1/4, y= (3/16+ 1/2)/(1/4)= 4(11/16)= 11/4= 2.75 x= 1/8, y= (3/64+ 1/4)(1/8 )= 8(19/64)= 9/8= 1.125 etc. You don't have to choose one over powers of two that was my choice. Just a sequence of number getting closer and closer to 0. But you really should not have to look at numbers like that for one thing there exist functions such that you can get "closer and closer" to what looks like a limit but then, when you are really close, suddenly change. Instead use the fact that and, as long as x is not 0, those 'x's cancel: . The limit, as x goes to 0, is 3(0)+ 2= 2. 

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