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October 13th, 2016, 12:09 PM   #1
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Quick question about complex numbers

So, I just started learning about complex numbers, and there has been one thing that has boggled my mind. I know how to convert simple complex numbers from rectangular form to polar form.

This might sound stupid but, how do I write $\displaystyle 16 - 0i$ in polar form (since there are no angles to figure out)?

Last edited by skipjack; October 24th, 2016 at 07:15 AM.
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October 13th, 2016, 02:56 PM   #2
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$16 + i0 = \sqrt{16^2 + 0^2}~ e^{i \arctan(0/16)} = 16 e^{i0} = 16$
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October 13th, 2016, 04:10 PM   #3
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Positive real number - angle = 0, negative real number - angle = $\displaystyle \pi $.
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October 14th, 2016, 02:27 AM   #4
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Thank you so much guys!
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