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October 13th, 2016, 12:09 PM  #1 
Newbie Joined: Oct 2016 From: Sweden Posts: 2 Thanks: 0  Quick question about complex numbers
So, I just started learning about complex numbers, and there has been one thing that has boggled my mind. I know how to convert simple complex numbers from rectangular form to polar form. This might sound stupid but, how do I write $\displaystyle 16  0i$ in polar form (since there are no angles to figure out)? Last edited by skipjack; October 24th, 2016 at 07:15 AM. 
October 13th, 2016, 02:56 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,405 Thanks: 1306 
$16 + i0 = \sqrt{16^2 + 0^2}~ e^{i \arctan(0/16)} = 16 e^{i0} = 16$

October 13th, 2016, 04:10 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,730 Thanks: 689 
Positive real number  angle = 0, negative real number  angle = $\displaystyle \pi $.

October 14th, 2016, 02:27 AM  #4 
Newbie Joined: Oct 2016 From: Sweden Posts: 2 Thanks: 0 
Thank you so much guys!


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