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 September 25th, 2016, 08:28 AM #1 Member   Joined: Aug 2016 From: illinois Posts: 46 Thanks: 0 Simplification help if you have an integral with 1 -cos^2(x) in it and then apply the half angle formula and then get the integral of 1-(1/2*cos(4x)). How would you simplify it to get the integral of (1/2)-(1/2)*cos(4x). The problem is on the bottom of this page.. Calculus II - Integrals Involving Trig Functions
September 25th, 2016, 08:40 AM   #2
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Quote:
 Originally Posted by fivestar if you have an integral with 1 -cos^2(x)
why would you do that?

$1-\cos^2(x) = \sin^2(x) = \dfrac{1-\cos(2x)}{2}$

 September 25th, 2016, 09:50 AM #3 Member   Joined: Aug 2016 From: illinois Posts: 46 Thanks: 0 Nvm I figured it out. I did that so I can have a integral that I can solve easily

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