September 19th, 2016, 01:16 PM  #11  
Member Joined: Sep 2013 Posts: 83 Thanks: 0  Quote:
 
September 19th, 2016, 01:42 PM  #12  
Member Joined: Sep 2013 Posts: 83 Thanks: 0  Quote:
$\displaystyle U= \frac {D}{C \frac{S^{2}}{C}}$ Last edited by Ku5htr1m; September 19th, 2016 at 01:53 PM.  
September 20th, 2016, 05:43 AM  #13 
Member Joined: Sep 2013 Posts: 83 Thanks: 0 
One more thing, i picked up what i believe is an error on that same slide: From this: $\displaystyle \beta *l+\sigma *\left \{ \frac{\alpha p_{x}\sigma *l}{\beta } \right \}=\alpha p_{l}$ To this: $\displaystyle l=\frac{\beta \sigma }{\beta ^2\sigma ^2}*\alpha \frac{\beta }{\beta ^2\sigma ^2}*p_{l}+\frac{\sigma }{\beta ^2\sigma ^2}*p_{x} $ i believe it should be : $\displaystyle l=\frac{\beta \sigma }{\beta \sigma ^2}*\alpha \frac{\beta }{\beta \sigma ^2}*p_{l}+\frac{\sigma }{\beta \sigma ^2}*p_{x}$ 
September 20th, 2016, 07:49 PM  #14 
Senior Member Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry 
I wonder how you can use LaTeX perfectly fine to write fractions but not for the multiplication symbol ($\displaystyle \times$).

September 21st, 2016, 07:06 AM  #15 
Member Joined: Sep 2013 Posts: 83 Thanks: 0  
September 21st, 2016, 07:20 AM  #16  
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 551  Quote:
$l( \beta^2  \sigma^2 ) = \beta ( \alpha  p_l)  \sigma (\alpha  p_x) = \alpha \beta  \beta p_l  \alpha \sigma + \sigma p_x = ( \beta \sigma ) \alpha  \beta p_l + \sigma p_x \implies$ $l = \dfrac{\beta  \sigma }{\beta^2  \sigma^2} * \alpha  \dfrac{\beta}{\beta^2  \sigma^2} * p_l + \dfrac{\sigma}{\beta^2  \sigma^2} * p_x.$ The slide looks good to me. Are you sure you are mathematically ready for this course?  
September 21st, 2016, 08:01 AM  #17  
Member Joined: Sep 2013 Posts: 83 Thanks: 0  Quote:
how did you get $\displaystyle \beta^2l $  
September 21st, 2016, 08:11 AM  #18 
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 551  
September 21st, 2016, 08:15 AM  #19 
Member Joined: Sep 2013 Posts: 83 Thanks: 0  ah ok i only multiplied it with the right side, i thought it was enough?
Last edited by Ku5htr1m; September 21st, 2016 at 08:22 AM. 
September 21st, 2016, 09:37 AM  #20 
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 551 
You must not alter the value of one side of the equation without altering the other side the same way. This is basic algebra, taught in the first week or two of the subject. Seriously and intended helpfully, whatever course you are taking appears as though it demands math at a level you are very uncomfortable with. I'd drop it for now and take a college algebra course and a calculus course before trying to deal with differential equations. 

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