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July 14th, 2016, 02:25 PM  #1 
Newbie Joined: Jul 2016 From: Brazil Posts: 1 Thanks: 0  physics calculation, help me please!
A car starts a curve with speed 50km / h. This curve is an arc of circumference with radius of 10 m. If it takes 10 seconds to describe this curve, and is a constant acceleration of 0.8 m / s, calculate: a) the angular velocity curve beginning and at the end thereof; b) Distance traveled this curve; c) Angle described the car; d) angular acceleration; e) centripetal acceleration at the beginning of the path; 
July 14th, 2016, 03:46 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,843 Thanks: 1484 
first, you need to convert the initial tangential velocity, $v_{0} = 50 \, km/hr$ to $m/s$ (a) ... $\omega_0 = r \cdot v_{0}$ assuming the given constant acceleration is tangential to the curve ... $v_{f} = v_{0} + a_T \cdot \Delta t$ and $\omega_f = r \cdot v_{f}$ (b) ... $\Delta s = r \cdot \bar{\omega} \cdot \Delta t = r \left(\dfrac{\omega_0+\omega_f}{2}\right) \cdot \Delta t$ (c) ... $\Delta \theta = \dfrac{\Delta s}{r}$ (d) ... $\alpha = \dfrac{\Delta \omega}{\Delta t}$ (e) ... $a_c = \dfrac{v_0^2}{r} = r \cdot \omega_0^2$ 
July 14th, 2016, 06:16 PM  #3  
Math Team Joined: Jul 2011 From: Texas Posts: 2,843 Thanks: 1484  Quote:
 

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