July 3rd, 2016, 07:29 AM  #1 
Member Joined: Feb 2014 Posts: 91 Thanks: 1  integrals sin and cos I seem to have a hole in my logic. I pulled out a constant from this which was 1/2. I put this constant on the outside of the integral sign. Their results are similar to mine except I have to multiply everything by a constant of 1/2 at the end. I think I messed up when I did U substitute but I haven't seen the mistake yet. Please help 
July 3rd, 2016, 08:45 AM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,313 Thanks: 2447 Math Focus: Mainly analysis and algebra 
We can't see your mistake because we can't see your working.

July 3rd, 2016, 08:52 AM  #3 
Math Team Joined: Jul 2011 From: Texas Posts: 2,755 Thanks: 1405 
where did you get the constant, $\dfrac{1}{2}$, from the integral shown ? $\displaystyle \int \sin^2{x}\cos^2{x} \sin{x} \, dx$ 
July 3rd, 2016, 10:01 AM  #4 
Member Joined: Feb 2014 Posts: 91 Thanks: 1 
I've consulted with others. This problem is $\displaystyle \int \sin^2{x}\cos^2{x} \, dx$ When I did my U substitution I let U be equal to cos^2x which was wrong. U should have just been cos(x). I revisited this question multiple time yesterday so I though I needed to ask here. Sorry for wasting your time my apologies. 
July 8th, 2016, 04:35 AM  #5  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,194 Thanks: 871  Quote:
 

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cos, integrals, sin 
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