My Math Forum (http://mymathforum.com/math-forums.php)
-   Calculus (http://mymathforum.com/calculus/)
-   -   differential equation (http://mymathforum.com/calculus/333322-differential-equation.html)

 jiasyuen June 26th, 2016 08:08 AM

differential equation

How to solve the differential equation $$x \frac{d^2y}{dx^2}+2(3x+1)\frac{dy}{dx}+3y(3x+2)=18 x$$

I think I could let $u=xy$, but I don't know how to proceed it.

 skipjack June 26th, 2016 02:04 PM

$xy = u$ implies $xy' + y = \dfrac{du}{dx}$ and $x\dfrac{d^2y}{dx^2} + 2\dfrac{dy}{dx} = \dfrac{d^2u}{dx^2}$.

Hence $\dfrac{d^2u}{dx^2} + 6\dfrac{du}{dx} + 9u = 18x$.

 All times are GMT -8. The time now is 04:56 PM.