January 13th, 2013, 03:12 AM  #1 
Senior Member Joined: Oct 2012 Posts: 460 Thanks: 0  arctan...
[color=#0000BF]Dear All! Please, if we have the function: then it should be isn't it? then we have the resul 0/x^2+1, isnt it true? but the result says the function is not defined at 1? why? as we habve rational function pol shoudl be x^2+1=0 so x^2=1 and it shou dnot have result in R shoudl it? the result says the function is constant on and [latex]((1, \infty[/latex dont get this...][/color] 
January 13th, 2013, 03:40 AM  #2 
Member Joined: Jul 2012 Posts: 60 Thanks: 0 Math Focus: Calculus  Re: arctan... "x" can't be 1 because in the initial equation you had "x1" in the denominator if "x" was 1 the the initial equation would have been: arctg(x+1)/(0) + arctg(x) 
January 13th, 2013, 07:06 AM  #3 
Senior Member Joined: Oct 2012 Posts: 460 Thanks: 0  Re: arctan...
[color=#0000FF]Hey,sorry, mymistakeagain...it should be the derivative from that function! I got the derivative is y'=0/x^2+1=0 then, for all x<1, the function should be pi/4,what I dont knowhow to get and for x>1f(x) should be arctan2+arctan3=2.35,what I cant get too... Please,can anyone help? Many thanks![/color] 
January 16th, 2013, 04:17 AM  #4 
Senior Member Joined: Oct 2012 Posts: 460 Thanks: 0  Re: arctan...
[color=#0000FF]Dear All! Please, how do we get that f'x(x)=0 f(0=arctan2+arctan3??? for x>1how do I get this? how do I get pi/4 for x<1??? there is a function: http://www.wolframalpha.com/input/?i=f% ... %2Barctanx Many thanks!!![/color] 

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