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January 13th, 2013, 03:12 AM   #1
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arctan...

[color=#0000BF]Dear All!
Please, if we have the function:



then it should be


isn't it?

then we have the resul 0/x^2+1, isnt it true?
but the result says the function is not defined at 1?
why?
as we habve rational function pol shoudl be x^2+1=0
so x^2=-1 and it shou dnot have result in R shoudl it?


the result says the function is constant on
and
[latex]((1, \infty[/latex
dont get this...]
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January 13th, 2013, 03:40 AM   #2
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Re: arctan...




















"x" can't be 1 because in the initial equation you had "x-1" in the denominator

if "x" was 1 the the initial equation would have been:

arctg(x+1)/(0) + arctg(x)
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January 13th, 2013, 07:06 AM   #3
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Re: arctan...

[color=#0000FF]Hey,sorry, mymistakeagain...it should be the derivative from that function!
I got the derivative is
y'=0/x^2+1=0

then, for all x<1, the function should be -pi/4,what I dont knowhow to get

and for x>1f(x) should be arctan2+arctan3=2.35,what I cant get too...
Please,can anyone help?
Many thanks!
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January 16th, 2013, 04:17 AM   #4
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Re: arctan...

[color=#0000FF]Dear All!
Please, how do we get that

f'x(x)=0
f(0=arctan2+arctan3??? for x>1how do I get this?
how do I get -pi/4 for x<1???


there is a function:
http://www.wolframalpha.com/input/?i=f% ... %2Barctanx


Many thanks!!!
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