My Math Forum Doubt with inverse Z transform

 Calculus Calculus Math Forum

 May 1st, 2016, 02:58 AM #1 Senior Member     Joined: Oct 2014 From: EU Posts: 224 Thanks: 26 Math Focus: Calculus Doubt with inverse Z transform Hi, I am not sure about an exercise I solved for Inverse Z transform.. Having $\displaystyle X(z) = {6 \over (z - 3)}$ I solved as: $\displaystyle {6 \over (z - 3)} = -{6 \over (3 - z)} = -{2 \over (1 - {z \over 3})} \Rightarrow -2(1/3)^n u[-n] = x[n]$ I deduce it from the time inversion property: \displaystyle \begin{aligned} x[-n] & \overset{\mathcal Z}{\longleftrightarrow} X(z^{-1})\\ u[n] & \overset{\mathcal Z}{\longleftrightarrow} {1 \over 1 - z^{-1}}\\ u[-n] & \overset{\mathcal Z}{\longleftrightarrow} {1 \over 1 - z}\\ \end{aligned} but I am not totally sure. Could someone confirm if I am right or wrong ? Thank you in advance.

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