May 1st, 2016, 02:58 AM  #1 
Senior Member Joined: Oct 2014 From: EU Posts: 224 Thanks: 26 Math Focus: Calculus  Doubt with inverse Z transform
Hi, I am not sure about an exercise I solved for Inverse Z transform.. Having $\displaystyle X(z) = {6 \over (z  3)}$ I solved as: $\displaystyle {6 \over (z  3)} = {6 \over (3  z)} = {2 \over (1  {z \over 3})} \Rightarrow 2(1/3)^n u[n] = x[n]$ I deduce it from the time inversion property: $\displaystyle \begin{aligned} x[n] & \overset{\mathcal Z}{\longleftrightarrow} X(z^{1})\\ u[n] & \overset{\mathcal Z}{\longleftrightarrow} {1 \over 1  z^{1}}\\ u[n] & \overset{\mathcal Z}{\longleftrightarrow} {1 \over 1  z}\\ \end{aligned} $ but I am not totally sure. Could someone confirm if I am right or wrong ? Thank you in advance. 

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doubt, inverse, transform 
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