My Math Forum  

Go Back   My Math Forum > College Math Forum > Calculus

Calculus Calculus Math Forum


Reply
 
LinkBack Thread Tools Display Modes
December 18th, 2012, 08:37 AM   #1
Newbie
 
Joined: Dec 2012

Posts: 23
Thanks: 0

prove there exists an inverse function

I'm quite new to calculus and frankly speaking I'm studying it on my own. Could you tell me how to solve this:



Prove that there exists an inverese of . In what set is differentiable? Calculate


I would really appreciate a thorough explanation. Thank you.
annakar is offline  
 
December 18th, 2012, 08:57 AM   #2
Math Team
 
Joined: Sep 2007

Posts: 2,409
Thanks: 6

Re: prove there exists an inverse function

Okay, do you remember the requirements that a function be invertible? In order that for any given y we be able to find the x such that y= f(x), there must be at least one such x (f is "onto") and there must be just one such x (f is "one-to-one"). Neither of those is true for sin(x) itself- there is NO x such that sin(x)= 2 and there exist infinitely many x such that sin(x)= 0. I would suggest starting by looking at graph of .
HallsofIvy is offline  
Reply

  My Math Forum > College Math Forum > Calculus

Tags
exists, function, inverse, prove



Search tags for this page
Click on a term to search for related topics.
Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
Proving that a limit of a function of two variables exists Akcope Real Analysis 6 February 19th, 2014 06:10 PM
Proving that a function exists eddybob123 Algebra 5 March 14th, 2013 11:56 PM
Simple prove why our universe and nature's laws exists. karel vdr Physics 6 August 1st, 2012 02:00 PM
Prove that there exists a quadratic polynomial R(x) mathLover Abstract Algebra 1 April 17th, 2012 02:19 AM
show that there exists an increasing function 450081592 Real Analysis 1 October 16th, 2011 12:26 AM





Copyright © 2019 My Math Forum. All rights reserved.