December 11th, 2012, 03:31 PM  #1 
Newbie Joined: Sep 2011 Posts: 29 Thanks: 0  Different axes of revolution
My program is to find the volume of the solid generated when y = x^2 bounded by y = 4, and x = 0 and revolved about the line y = 2... When they say it has a different axes of revolution do they mean they move the curve or do they mean the solid has a hole in it or what? 
December 11th, 2012, 03:35 PM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 466 Math Focus: Calculus/ODEs  Re: Different axes of revolution
This particular solid will have a hole in it.

December 11th, 2012, 04:02 PM  #3 
Newbie Joined: Sep 2011 Posts: 29 Thanks: 0  Re: Different axes of revolution
Thanks for the quick reply.

December 12th, 2012, 02:32 PM  #4 
Newbie Joined: Sep 2011 Posts: 29 Thanks: 0  Re: Different axes of revolution
Ok I have worked a couple of problems of these and I am not seeing how they get this answer for this particular problem I understand the x^2 + 2, a left shift, but where does that 36 come from? 
December 12th, 2012, 05:44 PM  #5 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 466 Math Focus: Calculus/ODEs  Re: Different axes of revolution
For an arbitrary washer, the outer radius is the distance between y = 4 and y = 2, which is 6 units. The square of this is 36.

December 13th, 2012, 04:37 AM  #6 
Newbie Joined: Sep 2011 Posts: 29 Thanks: 0  Re: Different axes of revolution
You are an asset to this forum. I got it now thanks. 

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