My Math Forum Different axes of revolution

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 December 11th, 2012, 03:31 PM #1 Newbie   Joined: Sep 2011 Posts: 29 Thanks: 0 Different axes of revolution My program is to find the volume of the solid generated when y = x^2 bounded by y = 4, and x = 0 and revolved about the line y = -2... When they say it has a different axes of revolution do they mean they move the curve or do they mean the solid has a hole in it or what?
 December 11th, 2012, 03:35 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 462 Math Focus: Calculus/ODEs Re: Different axes of revolution This particular solid will have a hole in it.
 December 11th, 2012, 04:02 PM #3 Newbie   Joined: Sep 2011 Posts: 29 Thanks: 0 Re: Different axes of revolution Thanks for the quick reply.
 December 12th, 2012, 02:32 PM #4 Newbie   Joined: Sep 2011 Posts: 29 Thanks: 0 Re: Different axes of revolution Ok I have worked a couple of problems of these and I am not seeing how they get this answer for this particular problem $\pi \int_0^2 (36 - (2+x^2)^2))$ I understand the x^2 + 2, a left shift, but where does that 36 come from?
 December 12th, 2012, 05:44 PM #5 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 462 Math Focus: Calculus/ODEs Re: Different axes of revolution For an arbitrary washer, the outer radius is the distance between y = 4 and y = -2, which is 6 units. The square of this is 36.
 December 13th, 2012, 04:37 AM #6 Newbie   Joined: Sep 2011 Posts: 29 Thanks: 0 Re: Different axes of revolution You are an asset to this forum. I got it now thanks.

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