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December 11th, 2012, 04:31 PM   #1
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Different axes of revolution

My program is to find the volume of the solid generated when y = x^2 bounded by y = 4, and x = 0 and revolved about the line y = -2...

When they say it has a different axes of revolution do they mean they move the curve or do they mean the solid has a hole in it or what?
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December 11th, 2012, 04:35 PM   #2
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Re: Different axes of revolution

This particular solid will have a hole in it.
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December 11th, 2012, 05:02 PM   #3
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Re: Different axes of revolution

Thanks for the quick reply.
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December 12th, 2012, 03:32 PM   #4
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Re: Different axes of revolution

Ok I have worked a couple of problems of these and I am not seeing how they get this answer for this particular problem



I understand the x^2 + 2, a left shift, but where does that 36 come from?
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December 12th, 2012, 06:44 PM   #5
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Re: Different axes of revolution

For an arbitrary washer, the outer radius is the distance between y = 4 and y = -2, which is 6 units. The square of this is 36.
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December 13th, 2012, 05:37 AM   #6
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Re: Different axes of revolution

You are an asset to this forum. I got it now thanks.
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