November 16th, 2012, 05:58 PM  #1 
Math Team Joined: Aug 2012 From: Sana'a , Yemen Posts: 1,177 Thanks: 44 Math Focus: Theory of analytic functions  A challenging integral 
November 17th, 2012, 04:43 AM  #2 
Senior Member Joined: May 2011 Posts: 501 Thanks: 6  Re: A challenging integral This can be evaluated with the Beta: Let This gives: This means that So, But, So, we have Now, using the identity: , we happily arrive at: 
November 17th, 2012, 04:56 AM  #3 
Math Team Joined: Aug 2012 From: Sana'a , Yemen Posts: 1,177 Thanks: 44 Math Focus: Theory of analytic functions  Re: A challenging integral
Really , I thought that can't be solved without using residues. Nice Approach [color=#0000BF]galactus[/color]. 

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